Question

1) x(x^2-1)+2-[x-(3-x^2)x]
2)(x-2)(x+3)-(x+1)(x-7)
3)3(x-2)+x(x-2)-x(x^2+x-1)
4)2-x(x+2)+(2-x)(3-x)-x(x^2-x+1)


~help with multiplying polynomials.

Answer 1

?

Answer 2

What is it about the multiplication of polynomials that is causing you trouble?

Answer 3

am I supposed to multiply everything outside the (parentheses?) like: 2-x(x+2) or am I just going to distribute the -x ?

Answer 4

distribute the -x

If the idea was to multiply everyting, then it should be written (2-x)(x+2)

Answer 5

x(x^2-1)+2-[x-(3-x^2)x]

So in this case, do x(x^2-1) first, then [x-(3-x^2)x] and finally add 2

In general do bracket things first...

Answer 6

and am I supposed to distribute it to (x+2) only?

Answer 7

What is the full question?

Answer 8

2-x(x+2)+(2-x)(3-x)-x(x^2-x+1) this one.

Answer 9

Yes, you can just think of that 2 sitting there waiting until you done something that it can be added to.

So (just for example), you have (2-x)(3-x) -> 6 -5x + x^2 and now you can add the 2 to that -> 8 -5x + x^2

Answer 10

2 -x(x+2) +(2-x)(3-x) -x(x^2-x+1)

There are 4 distinct pieces, you see?

Answer 11

oh okay! thank you so much :D

Answer 12

ur welcome

Answer 13

now you can go help AmberCat21 :-) http://openstudy.com/updates/505afe17e4b0cc122893d2ca