Question

Write the equation of the line that passes through (2, 2) and (6, 3) in standard form.

4x + 4y = 6

x + 4y = 12

4x + 4y = –12

x – 4y = –6

I have this so far I think it might be wrong.



3-2 =1
6-2 =4

Y-3 = 1/4(x-6)
Y-3 = 1/4x + 1.5

Answer 1

just a sign mistake :
Y-3 = 1/4(x-6)
Y-3 = 1/4x - 1.5
rest everything is correct.

Answer 2

then multiply 4 on both sides.

Answer 3

y-12=4x-1.5
-4x + y-12 = -1.5
-4x + y= 10.5
Awnser: 4x – y = -10.5

Answer 4

when u multiplied 4, 4*(1/4)x = x
and not 4x

Answer 5

and 4*y=4y

Answer 6

let me try it again

Answer 7

4y-3 = x -1.5
-x + 4y – 3 = -1.5
-x + 4y = 2.5
X – 4y = -2.5

Answer 8

But its still not an awnser

Answer 9

wait i will write the steps....
4(y-3)= 4/(1/4)x -4*1.5
4y-12 = x - 6
x-4y = -12+6
x-4y = -6
ask if there is doubt in any step..........

Answer 10

OK so i had to multiply the y And the 3. OK now I see where I was going wrong thank you for the help and being patient with me.

Answer 11

welocme :)