Find the zeros of the polynomial function, and state the multiplicity of each.
y = 4(x + 7)^2(x - 7)^3
These are the options: A. 4, multiplicity 1; -7, multiplicity 3; 7, multiplicity 3 B. -7, multiplicity 3; 7, multiplicity 2 C. 4, multiplicity 1; 7, multiplicity 1; -7, multiplicity 1 D. -7, multiplicity 2; 7, multiplicity 3
to find zeros, u put y=0 so u have 4(x + 7)^2(x - 7)^3 =0 that means (x + 7)^2=0 OR (x - 7)^3=0
So how do I find the zeros from those equations?
when (x-a)=0, a is a zero so when (x+7)=0 what will be the zero ?
not that easy yes to find zeros you have to put y=0 and then use wavy curve method to solve the zero
I am so confused.
hartnn, is it -7?
yes! and since it has power = 2 its multiplicity = 2
now u also have (x - 7)^3 =0 so what is a zro here ?
The zero is 7, and the multiplicity is 3. Is that right?
absolutely correct!
So the answer is B?
7, and the multiplicity is 3 so its D.
Oh, I see, whoops. Thanks so much! :)
welcome :)
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