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how do you solve this -3 √ -1000
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is that the negative third root of -1000?
yes
=(-1000)^(-1/3) = 1/((-1000)^(1/3)=1/-10 = -1/10
because the cube root of a negative is negative and the cube root of 1000 is 10
I replaced the cube root with the fractional exponent, is that okay by you?
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yes so the -3 = -1 and the -1000=-10 how did you get the positive
When you move a factor from the numerator to the denominator, the sign on the exponent switches. So A^-(1/3) = 1/A^(1/3)
oic ty
so the answer is -1 √ 10 or 1 √ -10
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