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Mathematics 7 Online
OpenStudy (anonymous):

7(x-2=3(x+4)

OpenStudy (anonymous):

7(x-2) = 3(x+4) 7x-14 = 3x+12 7x-3x = 12+14 4x = 26 x = 26/4 = 13/2

OpenStudy (anonymous):

thank u

OpenStudy (anonymous):

2x + 1 < 5

OpenStudy (anonymous):

how do i solve 2x+1<5

OpenStudy (anonymous):

first get all the numbers on one side, it's just like an equation. so the first thing you do is subtract 1 onto the other side you'll have: 2x < 4 then divide both sides by 2 to get x by itself x < 2

OpenStudy (anonymous):

thankz

OpenStudy (anonymous):

sorry do i solve this 3x + 5 < 6x -1

OpenStudy (anonymous):

try getting all the variables on one side and the numbers on another then divide to get x by itself

OpenStudy (anonymous):

ok let me try if not help me plz

OpenStudy (anonymous):

i got x<4/3 that right?

OpenStudy (anonymous):

not quite. so you have 3x+5 < 6x-1, you want to get the numbers on one side, so you can either subtract 5 from both sides or add 1

OpenStudy (anonymous):

that gives me -6

OpenStudy (anonymous):

so you you have 3x < 6x-6 right?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

now get the variables on the other side without the number. so subtract 6x from both sides

OpenStudy (anonymous):

its 1

OpenStudy (anonymous):

so my answer is x<1

OpenStudy (anonymous):

no...3x-6x isn't 6x

OpenStudy (anonymous):

what's 3 -6

OpenStudy (anonymous):

-3

OpenStudy (anonymous):

correct, so you have -3x < -6

OpenStudy (anonymous):

divide both sides by -3

OpenStudy (anonymous):

it gives me 2

OpenStudy (anonymous):

and remember to switch the signs because you're dividing by a negative number

OpenStudy (anonymous):

so you have x > 2

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