How can this be factored a^2-2ab-8b^2
@marird15 Do you know how to factor a^2 - 2a - 8? I realize that is not the question asked but the factoring technique is similar.
Great. Would you post that here? Then, we can relate it to your question?
(a-4)(a+2) ^^Post this up?
Correct. Look at your work: a^2 - 2a - 8 = (a-4)(a+2) Compare that to the trinomial you want to factor: a^2-2ab-8b^2. How do they differ. Compare term by term.
the second one has two variables A and B
Yes. Think about the problem as: (a)^2 - 2 (a)(b) - 8 (b)^2 -4 and 2 will still be part of the factorization but will have to have the variable b with them. Any ideas on how to do that? Play with it a bit.
Hint: (a - ? ) * (a + ?) = a^2-2ab-8b^2
You know you need the -4 and the 2. You also need to account for the variable b.
What does -4b times 2b equal?
- 8b wouldn't it be (a-4b)(a+2b) ?
-4b times 2b equals - 8b^2. And, yes, (a-4b)(a+2b) = a^2-2ab-8b^2 Very good.
Yaay! okay thank u ! i understand now
Great. Thanks for hanging in there with me as we went through the process. It was fun.
Question? @marird15 Or, another problem to work?
oh no thanks that was it! :) @Directrix
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