Question

Please Help: Write an equation of the line that passes through (6, -10) and is perpendicular to the line that passes through (4, -6) and (3,-4)?

Answer 1

The product of the slopes of two perpendicular lines is -1.

So, first find the slope of the line that passes through the two points given using the formula
slope = (y1-y2)/(x1-x2) = (-6+4)/(4-3) = -2

slope of the line perpendicular to this one will b m x -2 = -1, -2m = -1, m = 1/2

So, the slope of the other line is:
(y+10)/(x-6) and that = 1/2
so we have
2y + 20 = x-6
2y = x - 26
y = x/2 -13

Answer 2

thank you so much.