Question

I need help solving for x using complete the square

3x^2-18x=12

@precal

Answer 1

Step 1: Divide by 3: x^2 - 6x = 4
Step 2: Make the Square: (x-3)^2 = 4
This gets you the square part but it isn't equal to step 1.
Step 3: Make the equation equivalent
(x-3)^2 = x^2 - 6x + 9
so the leftover part is 9. So to do this you just add 9 to the other side to get 13

(x-3)^2 = 13
Step 4: Take the Square Root of both sides
x-3 = + or - √13
Step 5: Make x on one side:
x = 3 + √13 AND
x = 3 - √13

That's about it.

Answer 2

can't ignore the 3 in the front

Answer 3

I will look at this later, have many things to do ........sorry
deadlines.......