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Mathematics 14 Online
OpenStudy (anonymous):

can you please check if i did this right?

OpenStudy (anonymous):

Give an example of a rational function that has no horizontal asymptote and a vertical asymptote at x = 1. Example for horizontal asymptote that has none. x+2 ------- x^2+9+3 Example of a vertical asymptote at x=1 (x-2)(x+3) ------ x-1

OpenStudy (eyust707):

not sure what your criteria are for the first one, but the second one is correct.

OpenStudy (anonymous):

no horizontal asymptote does not mean asymptote is \(y=0\) it means it doesn't have one so from before that means the degree of the numerator is larger than the degree of the denominator

OpenStudy (anonymous):

therefore unfortunately your answer is not correct. you have to make the degree of the top bigger than the degree of the bottom i can give you an example if you like

OpenStudy (anonymous):

ohhh sorry is this good ? x^3+2 ------- x^2+9+3

OpenStudy (anonymous):

i am pretty sure that the word AND in this question means they want one function that satisfies both conditions

OpenStudy (anonymous):

not two different functions, one with no horizontal asymptote, and a different one with a vertical asymptote at \(x=1\) you are correct to put the \(x-1\) in the denominator

OpenStudy (anonymous):

oh your right how do i do that

OpenStudy (anonymous):

well, i bet now you can figure it out you know what the denominator has to have right?

OpenStudy (anonymous):

x-1?

OpenStudy (anonymous):

yes

OpenStudy (anonymous):

and since that has degree 1, you numerator only has to have some degree larger than 1

OpenStudy (anonymous):

make is simple

OpenStudy (anonymous):

*it

OpenStudy (anonymous):

x^3+2 ------ x-1

OpenStudy (anonymous):

tada

OpenStudy (anonymous):

omg are you a teacher?

OpenStudy (anonymous):

i am a car

OpenStudy (anonymous):

lol seriously

OpenStudy (anonymous):

have you ever seen a 73 satellite?

OpenStudy (anonymous):

hahahaa!!!!!! lol your a smart car

OpenStudy (anonymous):

thanks

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