Question

In a triangle ABC, AD is the bisector of angle BAC and angle C is greater than angle B.
Prove that angle ADB > angle ADC.

Answer 1

Please help I have an exam tomorrow and need to get my doubts cleared.

Answer 2

@lgbasallote please please help ....

Answer 3

@lgbasallote help!!!!!

Answer 4

Can you help @Mimi_x3?

Answer 5

one min

Answer 6

AD is the bisector of angle BAC , so angle BAD = angle CAD
angle C >angle B
angle ADB =180-(ABD+BAD)
angle ADC = 180-(CAD+ACD)
since angle BAD = angle CAD
angle ADB =180-(BAD+ABD)
angle ADC =180-(BAD+ACD)
angle C >angle B
hence,
angle ADB > angle ADC.

Answer 7

Thanks wwe123.