Question

Integrate:
logx/(1+logx)^2

Answer 1

@mathguy1125 are those natural logs or log base ten?

Answer 2

put u= 1+ log x
so log x of numerator will be u-1.
can u then solve it ?

Answer 3

@Natural logs.
@hartnn It has a slicker way, apparently. A substitution.

Answer 4

hmmm.... i couldn't think of a substitution..... maybe e^x ??

Answer 5

I dunno. Help?
@TuringTest
@sauravshakya @hartnn @experimentX

Answer 6

didn't u try what i said ?

Answer 7

You are saying:
= 1/(1+logx) - logx/(1+logx)^2 Then?

Answer 8

nopes, i was saying to put u= 1+log x
dx = e^(u-1) du
then integrate by parts..