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Without doing any simplification, determine the domain of g(x)=(√x-3)^2+5 I got the domain to be [3, infinity) is that right?
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Is the square root sing including the (x-3)
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you can't have a neg under the radical, so you are on the right track I think
the square root is not included underneath the radical
so is it the square root of (x - 3) or is it square roof of x then minus 3?
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its the square root of x-3
If it is then you are correct
yep, I agree, you are right (but the "square root" is what I meant by "the radical")
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