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OpenStudy (anonymous):
find the limit if it exists:
lim x->-1 (x^3+1)/(x+1). i think there is no limit for this problem. i can't factor out the numerator
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OpenStudy (anonymous):
or am i allowed to just plug in the -1 and solve?
OpenStudy (anonymous):
even so i get a 0 for the denom making it have no limit?
hartnn (hartnn):
there is a limit
hartnn (hartnn):
factor x^3 +1
OpenStudy (cwrw238):
it u plug in x=-1 the expression = 0/0 which is indeterminate
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hartnn (hartnn):
\(\huge a^3+b^3=(a+b)(a^2-ab+b^2)\)
OpenStudy (anonymous):
(x+1)(x2-x+1) ?
hartnn (hartnn):
yup, now cancel x+1 from numerator and denominator
OpenStudy (anonymous):
(-1)^2-(-1)+1?
OpenStudy (anonymous):
final answer of 1?
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OpenStudy (anonymous):
3
OpenStudy (anonymous):
oh yes, sorry, forgot to change the signs
OpenStudy (anonymous):
no matter
hartnn (hartnn):
so u got 3 ?
OpenStudy (anonymous):
yep
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hartnn (hartnn):
\(\large \frak{\color{red}{WELCOME \quad TO \quad OPENSTUDY \quad:D}}\)
OpenStudy (anonymous):
lol
hartnn (hartnn):
this is your first day here, right ?
so a warm welcome :)
OpenStudy (anonymous):
:D hey i got a question for another problem. need to double check it. starting a new one!
hartnn (hartnn):
sure , go ahead :)
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