Question

What is the equation of the line in standard form that passes through the point (3, 4) and is parallel to the line y = –x + 6?

Answer 1

hi king, what nincomp was saying is there is two equation of the line there, but they are parallel to each other, means their slope m are equal

Answer 2

use the slope of this line y = –x + 6, to get the slope of the other line

Answer 3

to get the slope of that you can compare it to the equation of
y=mx+b
y = –x + 6
we see that mx=-x
so m=-x/x=-1=slope

Answer 4

haha ok, thats a good start lol,

now use m=-1and the the point (3, 4) to the formula y-y1=m(x-x1)

Answer 5

hi king are you getting it?

Answer 6

well might as well continue it lol....
using m=-1and the the point (3, 4)=(x,y) to the formula
y-y1=m(x-x1)
y-4=-1(x-3) ans or
y-4=-x+3
y=-x+3+4
y=-x+7 .....ans

Answer 7

hello
equation of the line is y=-x+b (some slope)

that passes through the point (3, 4) ;
4=-3+b
b=7
the equation is y = -x +7