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Mathematics 11 Online
OpenStudy (anonymous):

find the minimum y-value on the graph of y=f(x). f(x)=x^2+8x-7 The minimum y-value is y=

OpenStudy (anonymous):

Well the minimum would be -7. If you plug in 0 for x

OpenStudy (anonymous):

Nope

OpenStudy (anonymous):

sec im factoring it

OpenStudy (anonymous):

x+1 and x+7

OpenStudy (anonymous):

Ive got -4 for x

OpenStudy (anonymous):

So the answer would be(x+1)(x-7) That would be the minimum y value

OpenStudy (anonymous):

No the answer is -23

OpenStudy (anonymous):

thank you

OpenStudy (anonymous):

thats how much the vertex moved down and the -4 is how much it moved left

OpenStudy (anonymous):

Perfect thanx agian

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