Question

6. If ACB is a right angle, m<1 = 4y, and m<2 = 2y + 18, find m<2. (1 point)
12º
48º
36º
42º

Answer 1

here's a hint..
\[\angle ACB = m\angle 1 + m\angle 2 = 90\]
does that help? or do you need more help?

Answer 2

More please, if you don't mind.

Answer 3

what is the value of m<1 according to the problem?

Answer 4

4y?

Answer 5

right. and m<2 is?

Answer 6

2y+18

Answer 7

right. and i said m<1 + m<2 = 90

so 4y + 2y + 18 = 90

solve for y and tell me what you get

Answer 8

y=12?

Answer 9

So 12 is the answer?

Answer 10

nope. that's just y

Answer 11

m<2 = 2y + 18

so to solve m<2 you have to substitute y into 2y + 18

make sense?

Answer 12

Okay so it would be 4(12) +2(12)+18...?

Answer 13

no...substitute y into 2y + 18 only

Answer 14

so 2(12)+18

Answer 15

right

Answer 16

which equals 42?

Answer 17

right

Answer 18

so 42 is my answer?

Answer 19

yes

Answer 20

Thank you!! :)

Answer 21

welcome

Answer 22

Oh I have one more question, that goes to the same photo above.
4. What is another name for <1?
C
DCA
ACB
CDA

I choose CDA as my answer but I'm not sure if that's right.

Answer 23

or it might be DCA, I'm not sure.

Answer 24

that's how m<1 looks right?

Answer 25

Yes

Answer 26

can you identify the letter of the middle of that angle?

Answer 27

C?

Answer 28

right. C is the middle. and what are the endpoints?

Answer 29

A and D

Answer 30

So C would be inthe middle, right? so it would be DCA?

Answer 31

right

Answer 32

Thanks!