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63c^2-7?
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Factor out 7 first..
ok
ok ??
a^2 -b^2 form
There is factor 7 in 63 and 7 both meaning 7 is factor of 63 and 7 both.. So you can take it out by using distributive property..
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Yeah after taking 7 common you will get a^2 - b^2 form then apply: \[a^2 - b^2 = (a-b)(a+b)\]
oh a^2 -b^2 form no need ah?
There is need of it but after taking 7 factor out first...
ok plz wait solving
7(3c+1) (3c-1)
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