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Mathematics 21 Online
OpenStudy (anonymous):

63c^2-7?

OpenStudy (anonymous):

Factor out 7 first..

OpenStudy (anonymous):

ok

OpenStudy (anonymous):

ok ??

OpenStudy (anonymous):

a^2 -b^2 form

OpenStudy (anonymous):

There is factor 7 in 63 and 7 both meaning 7 is factor of 63 and 7 both.. So you can take it out by using distributive property..

OpenStudy (anonymous):

Yeah after taking 7 common you will get a^2 - b^2 form then apply: \[a^2 - b^2 = (a-b)(a+b)\]

OpenStudy (anonymous):

oh a^2 -b^2 form no need ah?

OpenStudy (anonymous):

There is need of it but after taking 7 factor out first...

OpenStudy (anonymous):

ok plz wait solving

OpenStudy (anonymous):

7(3c+1) (3c-1)

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