Question

suppose one geometric mean g and two arithmetic means l and m are inserted b/n two numbers, find\[g^{2}\] in terms of l and m.

Answer 1

m getting g = 2lm/(l+m)
g as HM between l and m

Answer 2

nope

Answer 3

x,l,g,m,y
g=\(\sqrt{xy}\)
l=(x+g)/2
m=(g+y)/2
solving for g, i got g = 2lm/(l+m)

Answer 4

g^2 =a*b
where a and b are the two numbers now is l-(m-l)=2l-m and b is m+m-l =2m-l
hence g^2= (2l-m)(2m-l)

Answer 5

Nope hartnn

Answer 6

is my answer correct @Zekarias

Answer 7

That is right matricked

Answer 8

closing