Question

plz help
a two digit num is such that the product of the digit is 12. when 36 is added to the number the digits interchange thier places. find quad eq?

Answer 1

here's a hint..

the factors of 12 (that are consisted of 1 digit times 1 digit) are

3 x 4

4 x 3

6 x 2

2 x 6

does that help?

Answer 2

find the quad equation

Answer 3

huh? aren't you asking for the number?

Answer 4

this question is vague

Answer 5

very vague

Answer 6

the number is 26

Answer 7

let the digit in the tenth place be x then the digit in the units place is 12/x
hence orig number =10x+12/x
now after the digits interchange is 10*12/x + x
by the problem (10x+12/x)+36=120/x +x .... and so on

Answer 8

y u hve tkn 12/x . y nt 12x

Answer 9

@matricked I don't think you are correct

Answer 10

Let the number be written as xy, thus
x*y=12 and
10x+y+36 = 10y+x
solve this

Answer 11

bcoz the product of the numbers is 12 hence if any one is x the other has to be 12/x

Answer 12

right

Answer 13

36=108/x -9x or 4=12/x -x
or the reqd quad is 4x =12 -x^2
or x^2 + 4x -12 =0 or factorising (x+6)(x-2)=0 hence x=2 (neglecting -6 as it doesn't satisfy the question)
hence the number is 10x+12/x =20 +6=26