Question

1

Answer 1

calculAate slopes of three lines

Answer 2

AB, BC, CA

Answer 3

if the product of any two slopes is -1, they are perpendicular

Answer 4

they are at right angles to each other

Answer 5

u know that if product of slopes is -1, the two lines are at 90 degrees

Answer 6

the main condition of right triangle is to sides make 90 degree and we can also call it perpendicular to each other

Answer 7

for AB
m = 2-4/-3-3

Answer 8

so, if the product of slopes of any two lines is -1, they are at 90 degrees to each other..and so the triangle is a right angle

Answer 9

anytime :)

Answer 10

the slope of ab is -1??

Answer 11

how do you calculate slope if two points are given?

Answer 12

if slope is not covered in ur class yet, you can use the distance forumula and calculate side lengths, and see if it fits pythagoras.. .

Answer 13

3-(-3)/4-2

Answer 14

hmm hw did you get 5/-1

Answer 15

the formula is (y2-y1)/(x2-x1)

Answer 16

get it

Answer 17

slope of a line given points \(A(\color{green}{x1},\color{purple}{y1}) , B(\color{green}{x2},\color{purple}{y2})\) = \(\frac{\color{purple}{y2-y1}}{\color{green}{x2-x1}}\)

Answer 18

I know that

Answer 19

we need to find slopes of all 3 sides

Answer 20

so now AC

Answer 21

i'll do for BC, u do for AB and AC similarly :
\(\large m=\frac{2-(-4)}{-3-(-1)}=\frac{2+4}{-3+1}=\frac{6}{-2}=-3\)

Answer 22

@uzumakhi already calculcate slope of AB = 1/3, so... .

Answer 23

oh, AB already calculated above, m=2/6=1/3

Answer 24

*calculated

Answer 25

now note that slope of line AB and BC have product -3 *(1/3) = -1

Answer 26

this implies AB is perpendicular to BC
means ABC is right triangle.
got this ?

Answer 27

Is it a right triangel yes;no

Answer 28

what is it

Answer 29

yes

Answer 30

see the slope of ac is 3, of bc is -1/3

Answer 31

the product is -1

Answer 32

ok thx

Answer 33

:D

Answer 34

I'm sorry for taking so much time

Answer 35

@Falkqwer what is the problem now
@him1618 explain it so good