Ask your own question, for FREE!
Mathematics 25 Online
OpenStudy (ghazi):

a b/c

OpenStudy (ghazi):

@vikayefremova

OpenStudy (anonymous):

?

OpenStudy (ghazi):

\[9\frac{ 1 }{ 7 }=\frac{ (9+7)+1 }{ 7 }= \frac{ 63+1 }{ 7 }=\frac{ 64 }{ 7 }\]

OpenStudy (ghazi):

clear ??

OpenStudy (anonymous):

yes... clear :) thanks

OpenStudy (ghazi):

\[a \frac{ b }{ c}=\frac{ (a*c)+b }{ c }\]

OpenStudy (anonymous):

i will need this later on.. hope you dont mind if i look over it a few times later for help :)

OpenStudy (ghazi):

sure ...you can go through this anytime..you want to :)

OpenStudy (anonymous):

thanks :)

OpenStudy (ghazi):

:) YW

OpenStudy (ghazi):

it can't be simplified further ....64/7 is simplest form in fraction... do you have options?

OpenStudy (anonymous):

yes, A. 9.12 B. 9/63 C. 9 1/7 D. 1 2/7

OpenStudy (ghazi):

i reduced option C in the form of 64/7

OpenStudy (ghazi):

what exactly was your question?? right ... 9 1/7 = 64/7 so it is C

OpenStudy (anonymous):

but how can the answer be the same as the question. that is the question 9 1/7

OpenStudy (anonymous):

you have to multiply it

OpenStudy (ghazi):

does your question say multiply 9 and 1/7 ??

OpenStudy (anonymous):

yes, all you have to do is multiply :P

OpenStudy (ghazi):

if it is so then , \[9*\frac{ 1 }{ 7 }=\frac{ 9 }{ 7 }\] else can you take the screen shot and attach it here...because i am not getting your question and none of your options seems correct

OpenStudy (anonymous):

OpenStudy (anonymous):

sorry , i messed up for A. it's 9.17 not 9.12

OpenStudy (ghazi):

okay ...now i got it ..wait

OpenStudy (anonymous):

:)

OpenStudy (ghazi):

see \[9*\frac{ 1 }{ 7 }=\frac{ 9 }{ 7 }\] now if you look at your option D which is \[1\frac{ 2 }{ 7 }\] this will give you \[1\frac{ 2 }{ 7 }=\frac{ (7*1)+2 }{ 7 }=\frac{ 7+2 }{ 7 }=\frac{ 9 }{ 7 }\] clear ?? :D

OpenStudy (anonymous):

ahh.. okay i see now :D thank you :)

OpenStudy (ghazi):

cool ...also for the option C , already i have done a lot lol :) YW

OpenStudy (anonymous):

okay :)

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!