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4x^(3) - 16x^(2) - 20x factor completely. explain what goes on in the equation?
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take out the common factor of 4x 4x(x^2 - 4x - 5) all you need to do now is factorise the quadratic
x^2 -4x -5 how can you factorize it ?
i dont know.
ok... you need 2 factors of - 5 that add to - 4 5 is prime so you are using the factors 1 and 5 to get - 4
any ideas
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-5 + 1 ?
ok so you will have 4x(x - 5)(x + 1) all done
but where does the -5 and the +1 come from in the equation?
ok... if are you happy with taking 4x as a common factor to get 4x(x^2 - 4x - 5) the quadratic can be written as 4x(x^2 +x - 5x - 5)
thanks. that was more simple than i thought.
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