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A bicycle wheel with radius 26" rotates through an arc that measures 80°. What is the length of the arc of the tire that touched the ground?
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Find the circumference
is this the same ?
then multiply it by 80/360
I told you how to do it now you should be able to do it
104/9?
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or 11.5
circumference is : \[\Pi2r = \Pi d\]
\[52 \Pi\]
Yes, i got that
yeah but you forgot the pi
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And i did, 52pi*80/360
Oh
\[52 \Pi \times \frac{ 80 }{ 360 }\]
see you know how to do it, just put the pi back in
104/9 * pi
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that's it
\[104\pi/9\]
The pi times the whole set?
thats the answer ^^
the 104 pi / 9
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Okay, thank you AGAIN.
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