Question

Please help? Write an equation of a line that goes through point (4, –5) and is parallel to line y = 2x + 8. Show all work

Answer 1

do you know what parallel lines have in common?

Answer 2

yes the slope

Answer 3

ok... so you know the line you want has to have the same slope as that given line... what's the slope of that given line?
m= ???

Answer 4

2 also right?

Answer 5

yes... so now you have a point and slope...
do you know point-slope form: \(\large y-y_1=m(x-x_1) \) ???

Answer 6

just plug in those values.... \(\large (x_1, y_1) \rightarrow (4, -5) \)
slope: \(\large m=2 \)

Answer 7

Oh ok so 1 sec

Answer 8

so y - (-5)= 2(x-4)+8?

Answer 9

everything is correct except for that "+8" . where did that come from?

Answer 10

Am i supposed to plug that in cause its in the other equation or no?

Answer 11

no... just plug into this equation: \(\large y-y_1=m(x-x_1) \)
this equation gives you the line with the same slope and passing through the given point.
it's called point-slope form.

Answer 12

Oh okay thanks!(:

Answer 13

are you supposed to put it in slope-intercept form?

Answer 14

yw.... :)

Answer 15

all i had to do was simplify
I got y=2x-13

Answer 16

yep.... correct...:)