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Mathematics 11 Online
razor99 (razor99):

Factorize

razor99 (razor99):

81a^2-100

OpenStudy (swissgirl):

(9a+10)(9a-10) Its difference of squares

razor99 (razor99):

yep

razor99 (razor99):

swissgirl

razor99 (razor99):

@swissgirl

OpenStudy (swissgirl):

so you got it?

razor99 (razor99):

could u tell me the steps

razor99 (razor99):

i mean could u show it

OpenStudy (swissgirl):

I realized that we were missing the middle term Usually the equation is in the form \(ax^2+bx+c\) In this case the equation was in this form \(ax^2+c\) it was missing the bx So that means its difference of squares meaning that middle term canceled out

razor99 (razor99):

oh i get it thanx pippa u are a life saver

OpenStudy (swissgirl):

I am back should i finish off explaining or did u get it?

razor99 (razor99):

could u finish it

OpenStudy (swissgirl):

So anyways it is in the form \(a^2-b^2=(a-b)(a+b)\) \(81x^2-100=(9x-10)(9x+10)\) In this case our a=9x and b=10 So \(a^2=(9x)^2=81x^2 \text{ and } b^2=(10)^2=100\)

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