PLease solve: (gºf)(x)=g(f(x)): 3(1/3x+2)-6
I'm going to assume f(x) = 1/3x + 2 g(x) = 3x - 6 right?
yes
Okay, well distribute the 3 to finish simplifying
then 3/3=0 3*x=3x 3*2=6 so then the equation would look something like this? 3x+6-6=3x?
3/3 = 0? How?
I thought 3/3 = 1
any number over its clone = 1. For example, 1/1=1; 2/2=1; 654/654=1
The expression, if everything you wrote above is correct, should be: g(f(x)=x
but then how would i graph this?
Plug in values for x and solve for g(f(x)). My guess is you'll get something similar to the graph of y = x
This is a great resource by the way; http://www.khanacademy.org/math/algebra/quadtratics
@jwheele1, I get the feeling that she's trying to figure out how to graph g(f(x))
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