Question

Integrate [cos2a-cos2x/cosa-cosx] dx

Answer 1

write cos 2a as 2cos^2 a-1 and cos 2x as 2cos^x-1
then u get numerator as
2(cos^2 x + cos^2 a-1)
not sure this is best way,but try it out.....
isn't the numerator cos2a-cos2x ??

Answer 2

http://www.wolframalpha.com/input/?i=Integrate+%5Bcos2a%2Bcos2x%2Fcosa%2Bcosx%5D+dx&dataset=

Answer 3

i think saif meant this:
Integrate [(cos2a+cos2x)/(cosa+cosx)] dx
isn't it?

Answer 4

it is actually cos2a-cos2x/cosa-cosx....
really srry hartnn... :(