3x-y=0 2x-y=1 i am trying to solve these equations by graphing do you solve each equation first by putting it y=mx+b format
suggestion, add y to both sides
2x-y=1 2x-y+y=1+y 2x=1+y no we want to get rid of the 1 by subtracting 1 to both sides 2x-1=1-1+y 2x-1=y y=2x-1 that general process
I don't understand how you would graph these equations
the slope is m the y intercept is b y intercept means the point (0,b) slope is rise over run
I am so confused on this graphing part how do you get the answer to know how to graph them
the answer would be the point of intersection
i understand that but i don't understand how get the answer to graph them
did you graph them yet?
no because I don't understand how to
do you know what a coordinate point is?
no
oy... thats a problem
coordinate points come in the form of (x, y) |dw:1348416568549:dw|
oh okay I know what you mean now
teh easiest method to graph, cause i dont wnat to explain slope make a t chart |dw:1348416685689:dw| solve for y given a specific x, then plot the point then use a ruler to connect the point with a single line
so the equation would 3x-y=0 3x-y+y=0 3x=0+y so my point would be 3,0 for the first equation
no substitute for x, then solve for y if x =0, y=0 if x =1, y =3 if x=-1, y=-3
in this case, b=0, b is the y intercept the y intercept comes in the form of (0,b) the y interecept is (0,0)
slope means, from point to point, you go up 3 units and over 1
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