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Mathematics 20 Online
OpenStudy (anonymous):

(6x^2-21)/(x+1) Use synthetic division to divide I have done 5 different problems like this and I'm getting the wrong answers on all of them

Parth (parthkohli):

-1 | 6 0 -21 | -------------------- Here's the setup.

OpenStudy (anonymous):

I have done that setup and get the wrong answer all the time

OpenStudy (amistre64):

can you show us your steps Iam?

OpenStudy (anonymous):

it won't help now cause I got it wrong............. I'm working a new one now.

OpenStudy (anonymous):

(12^2-6)/(x+1) is the new problem

OpenStudy (anonymous):

there is supposed to be a x behind the 12

OpenStudy (amistre64):

same setup tho, different numbers can you run thru it with the example parth gave?

OpenStudy (anonymous):

what I came up with for this new problem is 12x12+6/x-1

OpenStudy (amistre64):

synthD needs all the parts filled in; the missing parts get zeros.

OpenStudy (amistre64):

12x^2 -6 ^^^ we need to fill in for the missing "x" to solve by synthD

OpenStudy (amistre64):

12x^2+0x -6 0 12 12 ------------- 1 ) 12x +12 R:6 i get the same results

OpenStudy (amistre64):

the divider is (x+1) tho isnt it

OpenStudy (anonymous):

it's tells me that is the wrong answer............ I get a hint from it........ The hint said Remember to place a 0 in as the coefficient for any missing powers of x

OpenStudy (amistre64):

using (x+1) instead: 12x^2+0x -6 0 -12 12 ------------- -1 ) 12x -12 R:6 \[12x-12+\frac6{x+1}\]

OpenStudy (anonymous):

that was the right answer...... I have been doing problems like for the 45 mins and always get the wrong answer

OpenStudy (amistre64):

you had that one pretty close :) at least you have a decent grasp on the concepts

OpenStudy (anonymous):

thank you

OpenStudy (amistre64):

youre welcome, and good luck

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