Question

Joe has a collection of nickles and dimes that is worth $4.35. If the number of dimes were doubled and the number of nickles were increased by 10, the value of the coins would be $7.05. How many dimes does he have?

Answer 1

Still there?

Answer 2

yep

Answer 3

Still working on this problem.

Answer 4

ok. 5n + 10d = 435 and 5(n+10) + 10(2d) = 705. Just solve for n and d.

Answer 5

That's where I was going with it, but I wasn't sure if that was correct.

Answer 6

It's right and I worked out the linear equations. There is only one intersection point (inpependent equations) so it's got one answer which works.

Answer 7

independent, not inpependent

Answer 8

Thank you

Answer 9

Hint: subtract one equation from the other and the nickels will drop out. You can then solve for dimes.

Answer 10

:) that is what I was doing. Glad I was on the right track.

Answer 11

Good luck to you and your studies.

Answer 12

22 dimes. Hope that's right.

Answer 13

Yes, 22 dimes.