Question

How do I find the zeros of: 3x^3 -48x

Answer 1

First factor out an x

Answer 2

x (3x -48)

Answer 3

then the zero property tells you that either term, x or 3x^2 - 48 can equal zero to solve this, so set each equal to zero independently and solve.

Answer 4

3x^2 - 48 = 0
3x ^2= 48
x^2= 16
x=4?

x=0?

so the zeros are x=4, and x=0?:S

Answer 5

don't forget the other solution to x^2 = 16...

Answer 6

x=-4 & x=4 ?

Answer 7

Yes, there are three zeros.

Answer 8

Well Done

Answer 9

thank you!