how do you find leg one and two of a right triangle with having all angle sides and the hypotenuse given?
If you are asking about a specific problem, please post it here. Thanks.
I was talking about in general, but as an example you have a right triangle (ABC, C=90 degrees) c= 24 find sides a and b angle A=25 B=65
Would you click on the blue DRAW tab and draw a picture of the triangle? Put the angle and side measures on the diagram. Be sure to mark the right angle. I think we'll need some right triangle trigonometry for this.
|dw:1348443709809:dw| does this make sense?
This makes great sense. Do you know the trig functions: sine, cosine, and tangent as related to side ratios of a right triangle?
yes, I missed a week of math and this is review from 2 years ago so I remember the Soh Cah Toa and I understand the inverse just not how to apply it to this problem
Look at angle A. Cos(25 degrees) = b/24. That equation comes from the cosine of an acute angle of a right triangle being the ratio of the adjacent leg to the hypotenuse. It's your turn. Do you remember how to get the cosine of 25 degrees?
I forgot to say that there is an online calculator if you don't have a physical one handy.
thank you so much, this makes sense!
Great but let's work the problem. Did you get cosine of 25 degrees?
yes, I worked out the problem, I got B= 65degrees as I already noted, and then for side b=22 and side a= 10
I got b = 21.75 approx. How did you get side a? Which trig equation?
I rounded for both answeres and used pythagorean therom!
Okay.
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