Solve the equation using square roots.

Question

anonymous · Answer

attachment

hartnn · Answer

Add 9 to both sides. what u get ?

anonymous · Answer

My choices:
A. –3, 3 	
B. –9, 9
$$-\sqrt{3}, \sqrt{3}$$
D. no real number solutions

hartnn · Answer

Add 9 to both sides. what u get ?

anonymous · Answer

C?

hartnn · Answer

Add 9 in both sides of x^2-9 =0
what u get?
u don't get direct answers here, sorry.

anonymous · Answer

@hartnn, I dont know how to... I get 81 - 9 = 0 which im pretty sure is wrong

anonymous · Answer

there after the answer ONLY!!

hartnn · Answer

how did u get 81 ?

anonymous · Answer

$$9^{2}$$

hartnn · Answer

why did u put x=9 ?

anonymous · Answer

what?

hartnn · Answer

u got 81 by 9^2 but why 9^2 ? keep it as x^2
u have x^2-9=0
Adding 9 to both sides,
x^2-9+9=0+9
x^2+0=9
x^2=9
can u solve this ?

anonymous · Answer

@hartnn  help me  for this problem Write an equation with the variable on each both side of the equal sign, at least one fractional cofficient, and a solution of-6. 
Thank you

hartnn · Answer

@Lovie03 i answered that, check it.

anonymous · Answer

how you get that

hartnn · Answer

@chicagochica5 

x^2=9
can u solve this ?

hartnn · Answer

taking square root on both sides,
x= +3 or x=-3

anonymous · Answer

@hartnn, im sorry I do not understand what to do or how to solve