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prove that x²-4x+3 is a factor of x⁵-5x⁴+7x³-2x²-4x+3
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Try this: \(\Large x^2-4x+3=(x-1)(x-3) \) If you can divide \(\Large x^5-5x^4+7x^3-2x^2-4x+3 \) by both factors of (x-1) and (x-3), then \(\large x^2-4x+3 \) is a factor of that long polynomial.
yes that worked, thank you !
Yw :)
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