Question

how to solve using the quadratic formula 4m(squared) - 25 = 0

Answer 1

Compare your quadratic equation with \(ax^2+bx+c=0\)
find a,b,c
then the two roots of x are:
\(\huge{x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}}\)

Answer 2

but I don't see b?

Answer 3

a=4 c=25 .. what is b? 1?

Answer 4

so b=0.
a=4 is correct
but c= -25

don't forget *minus* sign.

Answer 5

right right, ok, so plug in b as 0 in the calc

Answer 6

yup.

Answer 7

i love you!

Answer 8

i love u too, dear :)

Answer 9

so did u get +5/2 or -5/2 as your answer ?

Answer 10

no :( I got 40 somehow.. i don't think i'm putting it in right

Answer 11

can you help me work it out? I'm not sure how this one works...

Answer 12

sure.
\(\huge{\frac{-b \pm \sqrt{b^2-4ac}}{2a}}=\huge{\frac{-0 \pm \sqrt{^2-4(4)(-25)}}{2a}}\)
what is -4 * (4) *(-25)

Answer 13

-4 * (4) = - 16 * -25 = 400

Answer 14

and square root of 400 ?

Answer 15

20

Answer 16

yup, but u have + or minus sign also
so numerator is
+20 or -20
denominator = ?

Answer 17

8

Answer 18

so what is +20/8 or
-20/8 ?

Answer 19

5/2 or -5/2

Answer 20

aaaaahhhhhhhhhhhh

Answer 21

thats your final answer. any doubts anywhere.

Answer 22

how do i display this as the answer ?

Answer 23

i don't know how your system accepts.
possible representations are
5/2,-5/2
2.5,-2.5

Answer 24

thank you so much for your help!!

Answer 25

my pleasure
most welcome :)