Question

You drop a ball from a window 3.5m above the sidewalk. The ball accelerates at 9.8m/s2. How fast is ball moving when it hits the ground?

Answer 1

\[x = x_{0} + v_{0}t + 0.5at^2\]

Answer 2

Here, you know x0 (3.5m), v0 (initial velocity), and acceleration. X would be 0, because you want to know the time when it hits the ground.

Answer 3

I'm guessing you solved, but you can solve for t, then differentiate the above equation to get the equation for velocity. Plug that time in for t. Ba-da-bing...