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how do you solve for x in 2=\frac{-6}{x+4}
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\[2=\frac{-6}{x+4}\]
?
multiply both sides by (x+4)
Cross multiply. U will get 2(x+4)=-6 Then remove the brackets. U will get 2*x+2*4=-6 2x+8=-6 Subtract 8 both sides Divide by 2 both sides
\[2 (x+4 ) = -6\] \[2x + 8 = -6\] \[2x = -14\] \[x = \frac{ -14 }{ 2 } = -7\]
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