Question

solve the equation for exact solution over the interval of [0 - 2pi] : tan squared x + 3 = 0 .. help :)

Answer 1

\[\tan ^{2}x+3=0\]
is this the ?

Answer 2

yep :)

Answer 3

it looks like there is no solution
\[ \tan^{2} x=-3\]
undefined

Answer 4

really?
.. thats my assignmnt hehehe..

Answer 5

you can write
tan^2 x = -3
tan x = (-3)^1\2
\[\tan x = \sqrt{3}i\]

Answer 6

i think thats not it

Answer 7

\[\tan x = \tan \frac{ \Pi }{ 3 } i\]

Answer 8

\[x = \frac{ \Pi }{ 3 }i\]

Answer 9

have you study about imaginary numbers

Answer 10

yep

Answer 11

but we dont use imaginary in this part of the lesson i think

Answer 12

we have to use imaginery number when there is -ve sign in the squareroot

Answer 13

what do you say @camjan

Answer 14

yes i know but there is really something wrong.. try another one ill just post another pls answer tnx