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Mathematics 16 Online
OpenStudy (anonymous):

3x^2 + 17x + 10 factor completely?

OpenStudy (anonymous):

3x^2 + 15x + 2x + 10 does this help ?

OpenStudy (mayankdevnani):

\[3x^2+17x+10\]

OpenStudy (jiteshmeghwal9):

\[3x^2+15x+2x+10\]\[3x(x+5)+2(x+5)\]\[(3x+2)(x+5)\]

OpenStudy (mayankdevnani):

using splitting middle term method.... @ahoymewmew

OpenStudy (wwe123):

^^^that easy

myininaya (myininaya):

\[\text{ If you have } ax^2+bx+c , \text{ then I would find 2 factors of } a \cdot c \] \[\text{ that have product } a \cdot c\] \[\text{ that add up to be } b\] So here you have \[a=3,b=17,c=10\] So can you tell me the two factors of 3(10)=30 that have product 30 and sum 17?

myininaya (myininaya):

They have actually already told you. Next time it would probably be better to explain why you split the middle term up like that or try to get the asker to do some work.

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