Question

how do you solve for the complex fraction:
(3/2+x)-(4/2-x)
/(1/x+2)-(3/x-2)

Answer 1

find a common denominator for the tops, and subtract
ditto for the bottom fractions

then change the division by a fraction by inverting the bottom fraction and then multiplying

Answer 2

multiply top and bottom by \((x+2)(x-2)\) cancelling merrily as you go
clears the compound fraction in one step

Answer 3

alright i did that and cancelled out everything and got 2 for the answer...is that right?

Answer 4

is the problem
\[ \frac{ \frac{3}{2+x}-\frac{4}{2-x}}{\frac{1}{x+2}-\frac{3}{x-2}}\]

Answer 5

yup