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Find the solutions of the equation. x^3+3x^2+4x=0
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well just factor, you can simplify by taking out an x: x ( x^2 + 3x - 4) and then factor that into: x (x+4)(x-1) and then the solution's include 0, -4, and 1
that is not what the back of the book says
what does the back of the book say.
\[0, -\frac{ 3 }{ 2 }\pm \frac{ 1 }{ 2 }, \sqrt{7i} \]
type your equation again please cause the equation you typed has the answers i provided.
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\[x^{3}+3x^{2}+4x=0\]
oh ok..sorry so you can still factor out the x leaving you with (x^2 + 3x+4) and then use the quadratic formula..do you know the quadratic formula?
yes okay. now I know how they got it
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