x^2-x-2/2x^2-5x+2 (divided by) x^2-x-12/2x^2+5x-3

Question

zepdrix · Answer

wow this problem is evil :D algebra nightmare lol hmm ok lets see..

zepdrix · Answer

remember that when you divide fractions, it's the same as multiplying by the reciprocal of the denominator.
you take the bottom fraction and "flip it" and rewrite it as multiplication

anonymous · Answer

im more confused :-( @zepdrix

zepdrix · Answer

so you can rewrite this equation like so
$$\frac{ x^{2}-x-2 }{ 2x^{2}-5x+2 }*\frac{ 2x^{2}+5x-3 }{ x^{2}-x-12 }$$

zepdrix · Answer

D':

zepdrix · Answer

$$\frac{ (\frac{ a }{ b }) }{ (\frac{ c }{ d }) }$$
--->$$\frac{ a }{ b }*\frac{ d }{ c }$$

zepdrix · Answer

see what i did there? <:O the bottom fraction flips and the problem becomes multiplication instead of dividing 2 fractions

anonymous · Answer

:-( @zepdrix

zepdrix · Answer

lol :D

anonymous · Answer

im still confused can u do it step by step @zepdrix

zepdrix · Answer

hmm imma draw picture, its too hard to keep typing out that thing lol

zepdrix · Answer

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ok this is the first step D: so try to wrap yer head around it. i rewrote the example using simple letters next to it