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evaluate the limit algebraically (attached)
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\[\lim_{x \rightarrow 2+} \frac{ x+3 }{ 2 }\]
plug 2, gives (2+3)/2 = 2.5
oh... hahah didnt realize it was that easy. thanks.
can you show me how to do another one?
link?
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\[\lim_{y \rightarrow 0-} \frac{ \left| y \right| }{ y }\] i dont understand how the answer is -1
ok, 0- means it goes from left and it approaches 0
so 0- is a veryyyyyyy small number, and since its at 0's left, it is a negative number
something like -0.00000000000000000000000001
now put that into the equation and see what u get
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-1 thanks!
np ;)
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