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Given that √(5-2(√6))=√a-√b, find the values of 'a' and 'b'
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\[\sqrt{5-2\sqrt{6}}=\sqrt{a}-\sqrt{b}\]
try squaring both sides
I am not quite sure if I am doing this right \[5-2\sqrt{6}=(\sqrt{a}-\sqrt{b})^{2}\] \[(\sqrt{a}-\sqrt{b})^{2}=(\sqrt{a}-\sqrt{b})(\sqrt{a}-\sqrt{b})\] \[5-2\sqrt{6}=a-2\sqrt{ab}+b\]
yup looks good so far
oh so a+b=5 and a*b=6, solve for a and b
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exactly
the a will be 3 and b will be 2
except only issue would be determining which one is a and which one is b
oh, ya
oh wait a= higher number cant get a negative from a square root
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ok, thank you so much!!!!
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