what is the LCD for 50 and 30?
the smallest common multiple .... can be determined by breaking them downinto their prime products; then seeing what you have to include to equal them out
the prime factorizations are: 50 = 2*5*5 30 = 2*3*5 one manner to determine how to fill in the rest is to line them up so that like values are above like values 2 5 5 2 3 5 now drop everything down -------- 2 3 5 5 these are the prime factors of the LCD
so 150 is the answer. thank you :)
i like 150, good luck ;)
thanks :)
so we take the product of the disjunct of the factors of each number
i thought about trying to state it in set terms as well, but most proper sets dont accept multiples of the same element.
if we consider the factors to be distinct, regardless of multiplicity, then yes
hmmm
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