Y+4=-4(x-2) what point does this line pass through, which is the basis of this equation.
you have a point slope form of a line
the basis point is used in the equation itself as the add ons to x and y
negate the addons, and you have the point
So the answer would be (4,2)
almost .... but not quite
since a point is defined as (x,y) lets start with the x part, what is added onto the x part inthe equation?
y+4=-4(x-2) ^^ this part right here
2 or x or -4
im not sure that that response means
I'm not sure wat the was so ii put down all possiblities.
:) ok the portion that is added onto the x part y+4=-4(x-2) ^^ is this part right here, -2 the negation of -2 is: 2 the portion that is added onto the y part y+4=-4(x-2) ^^ is this part right here, +4 the negation of +4 is: -4 can you reconstruct the basis point now?
2,-4
that would be it :)
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