Y+4=-4(x-2) what point does this line pass through, which is the basis of this equation.
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OpenStudy (amistre64):
you have a point slope form of a line
OpenStudy (amistre64):
the basis point is used in the equation itself as the add ons to x and y
OpenStudy (amistre64):
negate the addons, and you have the point
OpenStudy (anonymous):
So the answer would be (4,2)
OpenStudy (amistre64):
almost .... but not quite
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OpenStudy (amistre64):
since a point is defined as (x,y)
lets start with the x part, what is added onto the x part inthe equation?
OpenStudy (amistre64):
y+4=-4(x-2)
^^ this part right here
OpenStudy (anonymous):
2 or x or -4
OpenStudy (amistre64):
im not sure that that response means
OpenStudy (anonymous):
I'm not sure wat the was so ii put down all possiblities.
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OpenStudy (amistre64):
:) ok
the portion that is added onto the x part
y+4=-4(x-2)
^^ is this part right here, -2
the negation of -2 is: 2
the portion that is added onto the y part
y+4=-4(x-2)
^^ is this part right here, +4
the negation of +4 is: -4
can you reconstruct the basis point now?