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What is the derivative of 2x^3
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by hand or power rule?
by hand
please
2x^3 rule: nx^n-1 n=3 so (3)2x^3-1 =6x^2
Sorry I need it by hand suka
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\[\lim_{h\to 0}\frac{2(x+h)^3-2x^3}{h}\] \[=2\lim_{h\to 0}\frac{(x+h)^3-x^3}{h}\] \[=2\lim_{h\to 0}\frac{x^3+3x^2h+3xh^2+h^3-x^3}{h}\] get rid of the \(x^3\) up top, factor out an \(h\) to cancel with the \(h\) in the denominator, then replace \(h\) by zero
Thanks man
yw, hope steps are clear, and don't forget that 2 out front
is it 3*2x^2=6x^2
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