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how do i factor 16a^2 - 4b^2
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note that each term is a perfect square this is the difference of 2 squares so use the identity x^2 - y^2 = (x + y)(x - y) here x = 4a and can u say what y = ?
4(2a+b)(2a-b)?
16a^2 - 4b^2 yes - you can simplify first by taking out 4: = 4 (4a^2 + b^2) = 4(2a + b)(2a - b)
thank you
yw
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