Question

Which of the following is a solution to the equation log 4 x + log 4 (x – 3) = 1 ?



x = 6/5

x = 2

x = –3

x = 4


In my part, I know that I need to multiply the logs which I get

log x^2-3x = 1

Or am I doing it wrong : P

Answer 1

I found out that it's

x -y
- + --
(x-y)(x+y) (x-y)(x+y)

Any way to simplify it more?

Any help?

Answer 2

x[x^2 - y^2 ]+ y[x^2 - y^2]

taking x^2 - y^2 as common we can write

(x^2 - y^2)(x+y)

x^2 - y^2=(x+y)(x-y)

so it can be written as

(x+y)(x-y)(x+y) or (x+y)^2(x-y)

Answer 3

Weird, the answers are

1
-
x-y


1
-
x+y

-1
--
x+y


1
-
y-x


So I'm confused.