Question

lim h-->0
cosh-1/h...??

Answer 1

yup .. y it equal zero ?

Answer 2

what if i multiplied it with sinx or cosx ?

Answer 3

solve it with the new one and tell me ??

Answer 4

the key that it's used to solve the prove 1st of cosx is -sinx .but i got stacked :S

Answer 5

every dervitaiv prove can be used by a limit

Answer 6

i will find an answer iam sure :D

Answer 7

Dude..

Answer 8

If you take the derivative of cos(h)-1 you get -sin(h), and the derivative of the denominator, h is just 1, so now you have\[\lim_{h \rightarrow 0}\frac{-\sin(h)}{1}=0\]